2b^2+12b=60

Solution for 2b^2+12b=60 equation:

2b^2+12b=60

We move all terms to the left:

2b^2+12b-(60)=0

a = 2; b = 12; c = -60;
Δ = b2-4ac
Δ = 122-4·2·(-60)
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{39}}{2*2}=\frac{-12-4\sqrt{39}}{4}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{39}}{2*2}=\frac{-12+4\sqrt{39}}{4}
$